If it's not what You are looking for type in the equation solver your own equation and let us solve it.
20-5t^2=0
a = -5; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·(-5)·20
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20}{2*-5}=\frac{-20}{-10} =+2 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20}{2*-5}=\frac{20}{-10} =-2 $
| 6+1/3x=11 | | 7y-8y-2(y-1=-1 | | (1+x)(x/2)=378 | | -16(-4)+13=x | | 12x+6=3x+24 | | 6-5n=39 | | x^2+x=378 | | 5x/8+2=7x/12 | | -5-3w=4w-2w | | 3q+45=17 | | -88=1.3m-2.1m | | 19z-24z+6z=0 | | 2x^2−3x−1=0 | | 420+25x=70x+25x | | (6/7)=(7/2w) | | -8(x+6)=4(x-6 | | -3v+9(v-7)+21=6(v-7) | | x^+25=30 | | 2(m+.3)=1/6(12m+36) | | (x)+(x)+(3x+45)=180 | | 5x=36x-2 | | 13x+15(1-x)=13 | | 2.5x-8=5x+7 | | 3x*10=90 | | 26-q=-34 | | x+5(2x-3)=-(2x+2) | | 3(2c-4)=60 | | (X/2)+(y/4)=1 | | -(4x+6)=(5-8x) | | 6(x-7)=4x-28 | | 16=8{x-1} | | x(x-1)=-15 |